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  	< !-- Tangram
		     7 Elemente
		     Seitenlänge des Quadrates aller Figuren: 2a
		     Diagonale: a*sqrt(2) = b
		     2 gleichschenkelig rechtwinkelige Dreiecke Basis 2a
		     2 gleichschenkelig rechtwinkelige Dreiecke Basis a
		     1 Parallelogramm Basis a, Höhe a
				 1 Quadrat Seitenlänge b/4
				 1 gleichschenkelig rechtwinkeliges Dreieck Basis b/2
				 sqrt(2) = 1,414213562373095
         Näherung für sqrt(2): 577/408 = 1,41421568627451
         daher waehlen wir als a: 2*408 = 816
         a = 816
         2a = 1632
         b = 2308
         b/2 = 1154
         b/4 = 577
  	-->
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